[MS]Remove multiple spaces
Given a string with multiple delimiters in between words,you have to replace them with single space.
eg:" hello\t\t hii " is changed as " hello hii ".
eg:" hello\t\t hii " is changed as " hello hii ".
Given an integer n, write a function that returns count of trailing zeroes in n!. Examples: Input: n = 5 Output: 1 Factorial of 5 is 20 which has one trailing 0. Input: n = 20 Output: 4 Factorial of 20 is 2432902008176640000 which has 4 trailing zeroes. Input: n = 100 Output: 24
delimiters includes just spaces and tab?
ReplyDelete@anonymous you can consider it to include just spaces and tab..:)
ReplyDeletethen we can do it using queue.we keep on adding elements to the queue until we encountered delimiter.once a delimiter is encountered we just add a space in the queue ans skip all the delimiters...the process has to be repeated till we reach end of string
ReplyDelete@anonymous this should be done in a single parsing without using any extra space..:)
ReplyDeleteUsing counter :
ReplyDeletechar *remove_ts(char *str)
{
int i,z,count;
for(count=i=z=0;str[i];i++){
if(str[i]=='\t'||str[i]==' ')
count++;
else{
if(count){
str[z]=' ';
z++;
}
str[z]=str[i];
z++; count=0;
}
}
str[z]='\0';
return str;
}
@Trent yes your code will work fine except the case when string ends with multiple delimiter then in that case you will never enter else statement.so you should put count condition at the end before adding str[z]='\0'.please check..:)
ReplyDeleteyes i forgot that the last can be a space!
ReplyDeletehere a fix before str[z]='\0' :
if(str[i-1]==' '){str[z]=' '; z++;}