Given an integer n, write a function that returns count of trailing zeroes in n!. Examples: Input: n = 5 Output: 1 Factorial of 5 is 20 which has one trailing 0. Input: n = 20 Output: 4 Factorial of 20 is 2432902008176640000 which has 4 trailing zeroes. Input: n = 100 Output: 24
Give a pointer of the new string :
ReplyDeletechar *urlspace_alloc(char *str)
{
char *ptr,*p;
int x,i; for(x=i=0;str[i];i++) if(str[i]==' ') x++;
ptr=malloc(sizeof(char)*(i+(x*3)+1));
if(ptr==NULL) return NULL;
else{
for(x=i=0;str[i];i++){
if(str[i]==' '){
p=&ptr[x];
memcpy(p,"%20",3);
x+=3;
} else {
ptr[x]=str[i];
x++;
}
}
ptr[x]='\0';
}
return ptr;
}