Given a Binary Tree, find vertical sum of the nodes that are in same vertical line. Print all sums through different vertical lines. Examples: 1 / \ 2 3 / \ / \ 4 5 6 7 The tree has 5 vertical lines Vertical-Line-1 has only one node 4 => vertical sum is 4 Vertical-Line-2: has only one node 2=> vertical sum is 2 Vertical-Line-3: has three nodes: 1,5,6 => vertical sum is 1+5+6 = 12 Vertical-Line-4: has only one node 3 => vertical sum is 3 Vertical-Line-5: has only one node 7 => vertical sum is 7 So expected output is 4, 2, 12, 3 and 7
int multiply8bit(int m, int n)
ReplyDelete{
int mLow_nLow = (m & 0x00FF) * (n & 0x00FF);
int mHigh_nLow = ((m & 0xFF00)>>8) * (n & 0x00FF);
int mLow_nHigh = (m & 0x00FF) * ((n & 0xFF00)>>8);
int mHigh_nHigh = ((m & 0xFF00)>>8) * ((n & 0xFF00)>>8);
return mLow_nLow + (mHigh_nLow<<8) + (mLow_nHigh<<8) + (mHigh_nHigh<<16);
}