permutation of a string
write a recursive solution to print all the permutations of a string. It is assumed that there are no duplicates in the string.
Given an integer n, write a function that returns count of trailing zeroes in n!. Examples: Input: n = 5 Output: 1 Factorial of 5 is 20 which has one trailing 0. Input: n = 20 Output: 4 Factorial of 20 is 2432902008176640000 which has 4 trailing zeroes. Input: n = 100 Output: 24
void permutate( char[] str, int index )
ReplyDelete{
int i = 0;
if( index == strlen(str) )
{ printf(str);
return;
}
for( i = index; i < strlen(str); i++ )
{
swap( str[index], str[i] );
permutate( str, index + 1 );
swap( str[index], str[i] );
}
}
call initially permutate( "abcdefgh", 0 );