If the probability of observing a car in 30 minutes on a highway is 0.95, what is the probability of observing a car in 10 minutes (assuming constant default probability)?
let the probability of not observing a car in 10 min is p,then probability of not observing a car in 30 min is p*p*p = 1-0.95 =0.05 so required probability = 1-(0.05)^(1/3)
Given an integer n, write a function that returns count of trailing zeroes in n!. Examples: Input: n = 5 Output: 1 Factorial of 5 is 20 which has one trailing 0. Input: n = 20 Output: 4 Factorial of 20 is 2432902008176640000 which has 4 trailing zeroes. Input: n = 100 Output: 24
I think we have to take any exponential equation
ReplyDelete1-(0.05)^(1/3)
ReplyDelete@anonymous correct...
ReplyDeletelet the probability of not observing a car in 10 min is p,then probability of not observing a car in 30 min is p*p*p = 1-0.95 =0.05
ReplyDeleteso required probability = 1-(0.05)^(1/3)