Given a Binary Tree, find vertical sum of the nodes that are in same vertical line. Print all sums through different vertical lines. Examples: 1 / \ 2 3 / \ / \ 4 5 6 7 The tree has 5 vertical lines Vertical-Line-1 has only one node 4 => vertical sum is 4 Vertical-Line-2: has only one node 2=> vertical sum is 2 Vertical-Line-3: has three nodes: 1,5,6 => vertical sum is 1+5+6 = 12 Vertical-Line-4: has only one node 3 => vertical sum is 3 Vertical-Line-5: has only one node 7 => vertical sum is 7 So expected output is 4, 2, 12, 3 and 7
I think we have to take any exponential equation
ReplyDelete1-(0.05)^(1/3)
ReplyDelete@anonymous correct...
ReplyDeletelet the probability of not observing a car in 10 min is p,then probability of not observing a car in 30 min is p*p*p = 1-0.95 =0.05
ReplyDeleteso required probability = 1-(0.05)^(1/3)