Given a Binary Tree, find vertical sum of the nodes that are in same vertical line. Print all sums through different vertical lines. Examples: 1 / \ 2 3 / \ / \ 4 5 6 7 The tree has 5 vertical lines Vertical-Line-1 has only one node 4 => vertical sum is 4 Vertical-Line-2: has only one node 2=> vertical sum is 2 Vertical-Line-3: has three nodes: 1,5,6 => vertical sum is 1+5+6 = 12 Vertical-Line-4: has only one node 3 => vertical sum is 3 Vertical-Line-5: has only one node 7 => vertical sum is 7 So expected output is 4, 2, 12, 3 and 7
void polyadd(struct link *poly1,struct link *poly2,struct link *poly)
ReplyDelete{
while(poly1->next && poly2->next)
{
if(poly1->pow>poly2->pow)
{
poly->pow=poly1->pow;
poly->coeff=poly1->coeff;
poly1=poly1->next;
}
else if(poly1->powpow)
{
poly->pow=poly2->pow;
poly->coeff=poly2->coeff;
poly2=poly2->next;
}
else
{
poly->pow=poly1->pow;
poly->coeff=poly1->coeff+poly2->coeff;
poly1=poly1->next;
poly2=poly2->next;
}
poly->next=(struct link *)malloc(sizeof(struct link));
poly=poly->next;
poly->next=NULL;
}
while(poly1->next || poly2->next)
{
if(poly1->next)
{
poly->pow=poly1->pow;
poly->coeff=poly1->coeff;
poly1=poly1->next;
}
if(poly2->next)
{
poly->pow=poly2->pow;
poly->coeff=poly2->coeff;
poly2=poly2->next;
}
poly->next=(struct link *)malloc(sizeof(struct link));
poly=poly->next;
poly->next=NULL;
}
}