Given a Binary Tree, find vertical sum of the nodes that are in same vertical line. Print all sums through different vertical lines. Examples: 1 / \ 2 3 / \ / \ 4 5 6 7 The tree has 5 vertical lines Vertical-Line-1 has only one node 4 => vertical sum is 4 Vertical-Line-2: has only one node 2=> vertical sum is 2 Vertical-Line-3: has three nodes: 1,5,6 => vertical sum is 1+5+6 = 12 Vertical-Line-4: has only one node 3 => vertical sum is 3 Vertical-Line-5: has only one node 7 => vertical sum is 7 So expected output is 4, 2, 12, 3 and 7
cin>>X;
ReplyDeletei=sqrt(X);
j=sqrt(X-i*i);
while(i>=0 && i>=j)
{
if((i*i)+(j*j)==X)
{count = 1;break;}
i--;
j=sqrt(X-i*i);
}
if(count == 1)
cout<<"Yes";
else cout<<"No";